1.

`6.02xx10^(20)` molecules of urea are present in 100 mL of its solution. The concentration of urea solution is:A. 0.02 MB. 0.01 MC. 0.001 MD. 0.1 M Glucose.

Answer» Correct Answer - b
`"No. of moles of urea"=(6.02xx10^(20))/(6.02xx10^(23))`
=0.001 mol.
100 mL of solution has moles = 0.001
1000 mL of solution has moles
`=(0.001)/((10mL))xx(1000mL)=0.01 M.`


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