

InterviewSolution
Saved Bookmarks
1. |
`6.02xx10^(20)` molecules of urea are present in 100 mL of its solution. The concentration of urea solution is:A. 0.02 MB. 0.01 MC. 0.001 MD. 0.1 M Glucose. |
Answer» Correct Answer - b `"No. of moles of urea"=(6.02xx10^(20))/(6.02xx10^(23))` =0.001 mol. 100 mL of solution has moles = 0.001 1000 mL of solution has moles `=(0.001)/((10mL))xx(1000mL)=0.01 M.` |
|