1.

6 Men And 8 Women Can Complete A Work In 10 Days. 26 Men And 48 Women Can Finish The Same Work In 2 Days. 15 Men And 20 Women Can Do The Same Work In - Days.

Answer»

Let work done by 1 MAN in 1 day = m and work done by 1 woman in 1 day = b 

Work done by 6 men and 8 women in 1 day = 1/10 

=> 6m + 8b = 1/10

=> 60m + 80b = 1 --- (1)

Work done by 26 men and 48 women in 1 day = 1/2 

=> 26m + 48B = ½

=> 52m + 96b = 1--- (2)

Solving equation 1 and equation 2. We get m = 1/100 and b = 1/200

Work done by 15 men and 20 women in 1 day 

= 15/100 + 20/200 =1/4

=> TIME taken by 15 men and 20 women in doing the work = 4 DAYS

Let work done by 1 man in 1 day = m and work done by 1 woman in 1 day = b 

Work done by 6 men and 8 women in 1 day = 1/10 

=> 6m + 8b = 1/10

=> 60m + 80b = 1 --- (1)

Work done by 26 men and 48 women in 1 day = 1/2 

=> 26m + 48b = ½

=> 52m + 96b = 1--- (2)

Solving equation 1 and equation 2. We get m = 1/100 and b = 1/200

Work done by 15 men and 20 women in 1 day 

= 15/100 + 20/200 =1/4

=> Time taken by 15 men and 20 women in doing the work = 4 days



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