P Can Do A Work In 24 Days. Q Can Do The Same Work In 9 Days And R Ca

1.	P Can Do A Work In 24 Days. Q Can Do The Same Work In 9 Days And R Can Do The Same In 12 Days. Q And R Start The Work And Leave After 3 Days. P Finishes The Remaining Work In --- Days.
Answer» Work done by P in 1 DAY = 1/24 Work done by Q in 1 day = 1/9 Work done by R in 1 day = 1/12 Work done by Q and R in 1 day = 1/9 + 1/12 = 7/36 Work done by Q and R in 3 days = 3×7/36 = 7/12 Remaining work = 1 – 7/12 = 5/12 NUMBER of days in which P can FINISH the remaining work = (5/12) / (1/24) = 10 Work done by P in 1 day = 1/24 Work done by Q in 1 day = 1/9 Work done by R in 1 day = 1/12 Work done by Q and R in 1 day = 1/9 + 1/12 = 7/36 Work done by Q and R in 3 days = 3×7/36 = 7/12 Remaining work = 1 – 7/12 = 5/12 Number of days in which P can finish the remaining work = (5/12) / (1/24) = 10

P Can Do A Work In 24 Days. Q Can Do The Same Work In 9 Days And R Can Do The Same In 12 Days. Q And R Start The Work And Leave After 3 Days. P Finishes The Remaining Work In --- Days.

Answer»

Work done by P in 1 DAY = 1/24

Work done by Q in 1 day = 1/9

Work done by R in 1 day = 1/12

Work done by Q and R in 1 day = 1/9 + 1/12 = 7/36

Work done by Q and R in 3 days = 3×7/36 = 7/12

Remaining work = 1 – 7/12 = 5/12

NUMBER of days in which P can FINISH the remaining work = (5/12) / (1/24) = 10

Work done by P in 1 day = 1/24

Work done by Q in 1 day = 1/9

Work done by R in 1 day = 1/12

Work done by Q and R in 1 day = 1/9 + 1/12 = 7/36

Work done by Q and R in 3 days = 3×7/36 = 7/12

Remaining work = 1 – 7/12 = 5/12

Number of days in which P can finish the remaining work = (5/12) / (1/24) = 10

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