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P And Q Can Complete A Work In 15 Days And 10 Days Respectively. They Started The Work Together And Then Q Left After 2 Days. P Alone Completed The Remaining Work. The Work Was Finished In --- Days.

Answer»

WORK DONE by P in 1 day = 1/15

Work done by Q in 1 day = 1/10

Work done by P and Q in 1 day = 1/15 + 1/10 = 1/6

Work done by P and Q in 2 DAYS = 2 × (1/6) = 1/3

Remaining work = 1 – 1/3 = 2/3

Time taken by P to complete the remaining work 2/3 = (2/3) / (1/15) = 10 days

TOTAL time taken = 2 + 10 = 12 days

Work done by P in 1 day = 1/15

Work done by Q in 1 day = 1/10

Work done by P and Q in 1 day = 1/15 + 1/10 = 1/6

Work done by P and Q in 2 days = 2 × (1/6) = 1/3

Remaining work = 1 – 1/3 = 2/3

Time taken by P to complete the remaining work 2/3 = (2/3) / (1/15) = 10 days

Total time taken = 2 + 10 = 12 days



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