1.

6g of hydrogen is burnt in the presence of excess oxygen. The mass of water formed is:

Answer»

54 G
108 g
36 g
18 g

Solution :`underset("2 MOLES")(2H_(2))+O_(2) to underset("2 moles")(2H_(2)O)`
6gm= 3 moles
From EQUATION
2moles `H_(2)` = 2moles `H_(2)O`
`:.` 3 moles `H_(2)` = 3 moles `H_(2)O`
Now mass of `H_(2)O` = mass `xx` Molecular wt.
`= 3 xx 18= 54 g`


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