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80% of the radioactive nuclei present in a sample is found to remain undecayed after one day. The percentage of undecayed nuclei left after two days will be a. 64 b. 20 c. 46 d. 80A. a. 64B. b. 20C. c. 46D. d. 80 |
Answer» Correct Answer - a. 64 `lambda = (2.303)/(t) log ((N_(0))/(N))` `= (2.303)/(1) log ((100)/(80)) [t = 1 "day"]` `lambda = (2.303)/(2) log ((100)/(80)) [t = 2 "days"]` `(2.303)/(1) log ((100)/(80)) = (2.303)/(2) log ((100)/(N))` `((5)/(4))^(2) = (100)/(N)` `N = 64` |
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