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`._(88)X^(288) - 3alpha + beta rarr Y`. The element Y isA. `._(82) Pb^(216)`B. `._(82)Pb^(217)`C. `.(83)Bi^(218)`D. `._(83)Bi^(216)` |
Answer» Correct Answer - D Atomic No.: `88 - (3 xx 2) + (1xx1) = 83` Mass No.: `228 - (3 xx4) - (1 xx0) = 216` |
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