1.

""_(92)U^(235) experiences one alpha - decay and onebeta- decay. Find number of neutrons in the final daughter nucleus that is formed.

Answer»

SOLUTION :Let X and Y be the resulting nucleus after the emission of the ALPHA and beta particles respectively
`""_(92)U^(235) overset(alpha "decay") to ""_(90)X^(231)+ ""_(2)He^(4)`
`""_(90)X^(231) overset(beta "decay") to ""_(91)Y^(231) + ""_(-1)e^(0)`
Number of neutrons = Mass number - Atomic number = 231 -91 = 140


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