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""_(92)U^(235) experiences one alpha - decay and onebeta- decay. Find number of neutrons in the final daughter nucleus that is formed. |
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Answer» SOLUTION :Let X and Y be the resulting nucleus after the emission of the ALPHA and beta particles respectively `""_(92)U^(235) overset(alpha "decay") to ""_(90)X^(231)+ ""_(2)He^(4)` `""_(90)X^(231) overset(beta "decay") to ""_(91)Y^(231) + ""_(-1)e^(0)` Number of neutrons = Mass number - Atomic number = 231 -91 = 140 |
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