`._(92)U^(238)` emits `8 alpha-` particles and `6 beta-` particles. The `n//p` ratio in the product nucleus isA. `(62)/(41)`B. `(60)/(41)`C. `(61)/(42)`D. `(62)/(42)`

`._(92)U^(238)` emits `8 alpha-` particles and `6 beta-` particles. Th

1.	`._(92)U^(238)` emits `8 alpha-` particles and `6 beta-` particles. The `n//p` ratio in the product nucleus isA. `(62)/(41)`B. `(60)/(41)`C. `(61)/(42)`D. `(62)/(42)`
Answer» Correct Answer - A `8 alpha-` particle emission decreases the atomic mass number by `8xx4=32`. Thereofre ,a atomic mass number of product nucleus is `238-32=206`. `6 beta-` particles and `8 alpha-` particles emission decreases the atomic number of by `8xx2-6xx1=10`. Therefore, atomic number of product nucleus `=92-10=82`. `:. ` number of neutrons in nucleus `=206-82=124`. `:. (n)/(0)=(cancel(124)^(2))/(cancel(82)^(2))=(62)/(41)`

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