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A `0.001` molal solution of `[Pt(NH_(3))_(4)Cl_(4)]` in water had freezing point depression of `0.0054^(@)C`. If `K_(f)` for water is `1.80`, calculating the number f `Cl^(-)` ions furnished.A. `[Pt(NH_(3))_(4)Cl_(3)]Cl`B. `[Pt(NH_(3))_(4)Cl_(3)]Cl_(2)`C. `[Pt(NH_(3))_(4)Cl_(3)]Cl_(3)`D. `[Pt(NH_(3))_(4)Cl_(3)]Cl_(4)]`

Answer» Correct Answer - B
`DeltaT_(f)=imk_(f),0.0054=ixx1.8xx0.001`
`i=3`so it is `[Pt(NH_(3))_(4)Cl]Cl_(2)`


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