A 0.1 m solution of K2SO4 in water has freezing point of -0.43°C. W

1.	A 0.1 m solution of K2SO4 in water has freezing point of -0.43°C. What is the value of van’t Hoff factor if Kf for water is 1.86 K kg mol-1?
Answer» Given : m = 0.1 m, ΔT_f = 0 – (-0.43) = 0.43°C K_f = 1.86 K kg mol^-1, i = ? ΔT_f = i × K_f × m \(\therefore\) \(i = \frac{\Delta T_f}{K_f \times m} = \frac{0.43}{1.86 \times 0.1} = 2.312\) van’t Hoff factor = i = 2.312.

A 0.1 m solution of K2SO4 in water has freezing point of -0.43°C. What is the value of van’t Hoff factor if Kf for water is 1.86 K kg mol-1?

Answer»

Given : m = 0.1 m, ΔT_f = 0 – (-0.43) = 0.43°C

K_f = 1.86 K kg mol^-1, i = ?

ΔT_f = i × K_f × m

\(\therefore\) \(i = \frac{\Delta T_f}{K_f \times m} = \frac{0.43}{1.86 \times 0.1} = 2.312\)

van’t Hoff factor = i = 2.312.

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A 0.1 m solution of K2SO4 in water has freezing point of -0.43°C. What is the value of van’t Hoff factor if Kf for water is 1.86 K kg mol-1?

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