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A `0.2 molal` solution of `KCl` freezes at `-0.68^(@)C`. If `K_(f)` for `H_(2)O` is `1.86`, the degree of dissociation of `KCl` is a.`85%` , b.`83%` , c. `65%` , d. `90%`A. 0.75B. 0.83C. 0.65D. 0.92 |
Answer» Correct Answer - B `DeltaT=ixxK_(f)xxm` `0.68=ixx1.86xx0.2` `i=1.83` `alpha=(i-1)/(n-1)` `=(1.83-1)/(2-1)=0.83` Ionization = 83%]. |
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