1.

A `0.2 molal` solution of `KCl` freezes at `-0.68^(@)C`. If `K_(f)` for `H_(2)O` is `1.86`, the degree of dissociation of `KCl` is a.`85%` , b.`83%` , c. `65%` , d. `90%`

Answer» `DeltaT=ixxK_(f)xxm`
`0.68=I xx 1.86 xx0.2`
`i=1.83`
`alpha=(i-1)/(n-1)=(1.83-1)/(2-1)=0.83`
`Ionization=83%`


Discussion

No Comment Found

Related InterviewSolutions