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A `0.2 molal` solution of `KCl` freezes at `-0.68^(@)C`. If `K_(f)` for `H_(2)O` is `1.86`, the degree of dissociation of `KCl` is a.`85%` , b.`83%` , c. `65%` , d. `90%` |
Answer» `DeltaT=ixxK_(f)xxm` `0.68=I xx 1.86 xx0.2` `i=1.83` `alpha=(i-1)/(n-1)=(1.83-1)/(2-1)=0.83` `Ionization=83%` |
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