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A `10 g` mixture of glucose and urea present in `250 mL` solution shows the osomotic pressure of `7.4 atm` at `27^(@)C`. Calculate `%` composition of mixture. |
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Answer» Let the mixture contains a g glucose and b g urea. `:.a+b=10` …(i) Also, `7.4 xx 250/1000=[a/180 + b/60]xx0.0821xx300` `3a + b =13.52` …(ii) Solving Eqs. (i) and (ii), we get `a=1.76 g` `b=8.24 g` `%` of glucose =`(1.76/10) xx 100 =17.6` `%` of urea =`(8.24/10) xx 100 =82.4` |
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