1.

A 117 1/3 m long rope is cut into equal pieces measuring 7 1/3 m each. How many such small pieces are these?

Answer»

From the question it is given that,

The length of the rope =  117 1/3 m

= (117 × 3 + 1)/3

= 352/3 m

Then length of each piece measures = 7 1/3 m

= 22/3 m

So, the number of pieces of the rope = total length of the rope/ length of each piece

= (352/3)/ (22/3)

= (352/3) × (3/22)

= (16/1) × (1/1)

= 16

Hence, number of small pieces cut from the 117 1/3 m long rope is 16.



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