1.

A(2, 4) and B(5, 8), find the equation of the locus of point P such that PA2 – PB2 = 13.

Answer»

Let P(x, y) be any point on the required locus. 

Given, A(2,4), B(5, 8) and PA2 -PB2 = 13 

∴ [(x -2)2 + (y – 4)2 ] – [(x -5)2 + (y- 8)2] = 13 

∴ (x2 – 4x + 4 + y2 – 8y + 16) – (x2 – 10x + 25 + y2 – 16y + 64) =13 

∴ x2 – 4x+ y2 – 8y + 20 – x2 + 10x – y2 + 16y – 89 = 13 

∴ 6x + 8y- 69 = 13 

∴ 6x + 8y – 82 = 0 

∴ 3x + 4y – 41 = 0 

∴ The required equation of locus is 3x + 4y-41 = 0.



Discussion

No Comment Found