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A 2-ton vehicle travels at 20m/s on a road where the frictional force is 10% of the weight of the vehicle. What is the power required? (Assume g = 10m/s^2)(a) 220 kW(b) 240 kW(c) 420 kW(d) 440 kWI have been asked this question in my homework.Query is from Power topic in portion Work, Energy and Power of Physics – Class 11 |
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Answer» RIGHT option is (d) 440 kW Easiest explanation: WEIGHT of car = m X g = 2,000 x 10 = 20,000 N Frictional force = (10/100) x (20,000) = 2,000 N Total force (F) = 20,000 + 2,000 = 22,000 N Velocity (v) = 20 m/s P = F x v = 22,000 x 20 = 4,40,000 W = 440 kW. |
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