A 5% solution (by mass) of cane suger in water has freezing point of 271K. Calculate the freezing point of 5% glucose in water if freezing point of water is 273.15 K.

A 5% solution (by mass) of cane suger in water has freezing point of 2

1.	A 5% solution (by mass) of cane suger in water has freezing point of 271K. Calculate the freezing point of 5% glucose in water if freezing point of water is 273.15 K.
Answer» Given 5% solution of cane sugar w = 5 gms, W = 95 gms m = 342, `DeltaT_("f")=273.15-271=2.15` `DeltaT_("f")=(K_("f")xxw)/(m xx W)` `2.15=("K"_("f")xx5)/(342xx95)" …(1)` 5% solution of glucose w = 5 gms, W = 95 gms ltbrrgt m = 180, `DeltaT_("f")=` ? `DeltaT_("f")=(K_("f")xx5)/(180xx95)" "...(2)` Dividing equation (2) by Equation (1) `(DeltaT_("f"))/(2.15)=(K_("f")xx5)/(180xx95)xx(342xx95)/(K_("f")xx5)` `DeltaT_("f")=(342xx2.15)/(180)=4.085"K"` `:.` The freezing point temperature for `5%` glucose solution `=273.15-4.085=269.07" K"`

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A 5% solution (by mass) of cane suger in water has freezing point of 271K. Calculate the freezing point of 5% glucose in water if freezing point of water is 273.15 K.

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