1.

A 550 K, the `K_(c)` for the following reaction is `10^(4) mol^(-1) L` `X(g)+Y(g) hArr Z (g)` At equilibrium, it was observed that `[X]= (1)/(2)[Y]=(1)/(2)[Z]` What is the value of [Z] ( in mol `L^(-1))` at equilibrium ?A. `2xx10^(-4)`B. `10^(-4)`C. `2xx10^(4)`D. `10^(4)`

Answer» Correct Answer - A
`K_(c)=([Z])/([X][Y])`
`[X]=(1)/(2)[Y]=(1)/(2)[Z]=a` (say)
`:. [Z]=2a,[Y]=2a,[X]=a`
`:. 10^(4)=(2a)/(a.2a)`
or `a=10^(-4)`
`:. [Z]=2a=2xx10^(-4)`


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