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(a) A person can see clearly upto `80 cm`. He uses spectacles of `-0.80 dioptre`, how far can he see clearly ? (b) If a person uses spectacles of power `+ 1.0 dioptre`, what is the nearest distance of distinct vision for him ? Given that near point of the person is `75 cm` from the eye. |
Answer» (a) Here, `P = - 0.80 dioptre` `f = (100)/(P) = (100)/(-0.8) = - 125 cm` `v = - 80 cm, u = ?` As `(1)/(v) - (1)/(u) = (1)/(f)` `:. (1)/(u) = (1)/(v) - (1)/(f) = (1)/(-80) + (1)/(125)` `= (-25 + 16)/(2000) = (-9)/(2000)` `u = - (2000)/(9) = - 222.22 cm` The person can see objects upto `222.22 cm`. (b) Here, `P = 1.0 dioptre` `f = (100)/(P) = (100)/(1) = 100 cm` `u = ? v = - 80 cm`, As `(1)/(v) - (1)/(u) = (1)/(f)` `:. (1)/(u) = (1)/(v) - (1)/(f) = -(1)/(75) - (1)/(100) = (-4 - 3)/(300)` `u = -(300)/(7) = - 42.9 cm`. `:.` The nearest distance of distinct vision of the person is `42.9 cm` |
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