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The diameter of the pupil of human eye is about `2 mm`. Human eye is most sensitive to the wavelength `555 nm`. Find the limit of resolution of human eye. |
Answer» Here, `D = 2 mm = 2 xx 10^(-3)m` `lambda = 555 nm = 555 xx 10^(-9)m` Limit of resolution, `dtheta = (1.22 lambda)/(D) = (1.22 xx 555 xx 10^(-9))/(2 xx 10^(-3))` `= 3.39 xx 10^(-4)rad` `dtheta = 3.39 xx 10^(-4) xx ((180)/(pi))^(@)` `= 0.0194^(@) = 0.0194 xx 60 min = 1.2 min` |
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