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1. |
A central fringe of interference pattern produced by light of wavelength `6000 Å` is shifted to the position of 5th bright fringe by introducing thin film of `mu = 1.5`. Calculate thickness of the film. |
Answer» Correct Answer - 6 micron Here, `lambda = 6000Å = 6 xx 10^(-7) m` `n = 5, mu = 1.5, t =?` The basic relation used is that path difference introduced by film = Path diff. for the shift. `(mu - 1) t = n lambda` `t = (n lambda)/((mu - 1)) = 6 xx 10^(-6)m` `= 6 micron` |
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