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Among the two interfering monochromatic sources A and B, A is ahead of B in phase by `66^@`. If the observation be taken from point P, such that `PB-PA=lambda//4`. Then the phase difference between the waves from A and B reaching P isA. `156^(@)`B. `140^(@)`C. `136^(@)`D. `126^(@)` |
Answer» Total phase difference `=` initial phase difference `+` phase difference due to path `=66^(@)+(360^(@))/(lambda)xxDeltax` `=66^(@)+(360^(@))/(lambda)xx(lambda)/(4)=66^(@)+90^(@)=156^(@)` |
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