1.

Among the two interfering monochromatic sources A and B, A is ahead of B in phase by `66^@`. If the observation be taken from point P, such that `PB-PA=lambda//4`. Then the phase difference between the waves from A and B reaching P isA. `156^(@)`B. `140^(@)`C. `136^(@)`D. `126^(@)`

Answer» Total phase difference
`=` initial phase difference `+` phase difference due to path
`=66^(@)+(360^(@))/(lambda)xxDeltax`
`=66^(@)+(360^(@))/(lambda)xx(lambda)/(4)=66^(@)+90^(@)=156^(@)`


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