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Laser light of wavelength `630 nm` incident on a pair of slits produces an interference pattern where bright fringes are separated by `8.1 mm`. Another light produces the interference pattern, where the bright fringes are separated by `7.2 mm`. Calculate the wavelength of second light. |
Answer» Here, `lambda_(1) = 630 nm, beta_(1) = 8.1 mm` As `beta = ( lambda D)/(d)`, therefore, `(lambda_(2))/(lambda_(1)) = (beta_(2))/(beta_(1)) = (7.2)/(8.1) = (8)/(9)` `lambda_(2) = (8)/(9) lambda_(1) = (8)/(9) xx 630 nm = 560 nm` |
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