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(a) A simple pendulum is made by suspending a bob of mass 500 g by a string of length 1 m . Calculate its time period at a place where g = 10 m s^(-2) . (b) How will the time period in part (a) the affected if bob of mass 100 g is used, keeping the length of string unchanged ? |
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Answer» SOLUTION :(a) Given : l=1 m , g = `10 ms^(-2)` Time period `T = 2pi sqrt(l/g) = 2 XX 3.14 xx sqrt(1/(10))` `=1.99 ` s (b) On CHANGING the bob by another bob of different MASS, the time period will remain unaffected because it does not depend on the mass of bob. |
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