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A, B and C can do a job working alone in 50, 75 and 20 days respectively. They all work together for 4 days, then C quits. How many days will A and B take to finish the rest of the job?1). 202). 303). 184). 24 |
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Answer» Suppose unit work = 300 units (LCM of 50, 75 & 20) ∴ Work done by A in one day = 300/50 = 6 Work done by B in one day = 300/75 = 4 Work done by C in one day = 300/20 = 15 ∴ Work done by (A + B + C) in 4 days = 4 × (6 + 4 + 15) = 100 C quits after 4 days. ∴ Time taken by A and B together to complete 200 units = 200/(6 + 4) = 20 days |
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