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`A + B hArrC + D`. If finally the concentrations of A an d B are both equal but at equilibrium concentration of D will be twice of that of A then what will be the equilibrium constant of reaction.A. `4//9`B. `9//4`C. `1//9`D. 4 |
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Answer» Correct Answer - D `{:(,A+B,hArr,C+D,),("Initial",a,,a,),("At eqm.",a-x,a-x,x" "x,):}` But we are given that `x=2(a-x)` or `3x=2a` or `a=(3)/(2)x=1.5 x` `:. K=(x xx x)/((a-x)^(2))=(x^(2))/((1.5x-x)^(2))` `=(x^(2))/(0.25x^(2))=4` |
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