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A & B together finishes a work in 10 days. B & C together finishes same work in 18 days. A works 5 days on this work firstly then B worked for 10 days and the remaining work is done by C in 15 days. If C alone do this work then in how many days he will take to complete the work.1). 42 days2). 45 days3). 38 days4). 28 days |
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Answer» Work done by A & B in one DAY = 1/10 work Work done by B & C = 18 days Work done by B & C in one day = 1/18 work Let C finishes the work in x days. ∴ Work done by C in one day = 1/x ? B + C = 1/18 C = 1/x ∴ B = 1/18 – 1/x ? A + B = 1/10 ∴ A = 1/10 – (1/18 – 1/x) Total work done = 1 ∴ A × (5 days) + B × (5 days) + C × (10 days) = 1 5 × (1/10) + 5 × (1/18) + 10 × (1/x) = 1 10/x = 1 – (5/10 + 5/18) ∴ x = 45 days. C will complete the work 45 days. |
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