1.

A & B together finishes a work in 10 days. B & C together finishes same work in 18 days. A works 5 days on this work firstly then B worked for 10 days and the remaining work is done by C in 15 days. If C alone do this work then in how many days he will take to complete the work.1). 42 days2). 45 days3). 38 days4). 28 days

Answer»

WORK DONE by A & B = 10 days

Work done by A & B in one DAY = 1/10 work

Work done by B & C = 18 days

Work done by B & C in one day = 1/18 work

Let C finishes the work in x days.

∴ Work done by C in one day = 1/x

? B + C = 1/18

C = 1/x

∴ B = 1/18 – 1/x

? A + B = 1/10

∴ A = 1/10 – (1/18 – 1/x)

Total work done = 1

∴ A × (5 days) + B × (5 days) + C × (10 days) = 1

5 × (1/10) + 5 × (1/18) + 10 × (1/x) = 1

10/x = 1 – (5/10 + 5/18)

∴ x = 45 days.

C will complete the work 45 days.



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