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A bakery sells cookies in three boxes. The three boxes contain 60, 84 and 108 number of cookies. The baker wants to sells all the cookies in any of the three boxes. The least number of cookies that he can bake, in a day, so that he is able to sell all his cookies in any of the three boxes is _______(a) 5467(b) 2243(c) 1123(d) 3780I had been asked this question during an online interview.Question is from Real Numbers in chapter Real Numbers of Mathematics – Class 10

Answer»

Right answer is (d) 3780

Easiest explanation: The THREE BOXES contain 60, 84 and 108 number of cookies.

60 can be factorized as 2 × 2 × 3 × 5, 84 as 2 × 2 × 3 × 7 and 108 as 2 × 2 × 3 × 3 × 3

To FIND the least number of cookies that can be FILLED in the container, we have to find the LCM of the three numbers

LCM of 60, 84 and 108 = 2 × 2 × 3 × 3 × 3 × 5 × 7 = 3780

Hence, the least number of cookies that can be filled in the container is 3780.



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