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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

The product of sec 30° and cos 60° is _____(a) 0(b) 2(c) 1(d) \( \frac {1}{\sqrt 3}\)This question was addressed to me in a national level competition.My doubt stems from Trigonometric Ratios ofSpecific Angles topic in chapter Trigonometry of Mathematics – Class 10

Answer»

Correct option is (d) \( \frac {1}{\SQRT 3}\)

The explanation: (SEC 30°) (cos 60°) = \(( \frac {2}{\sqrt 3}) ( \frac {1}{2} )\)

= \( \frac {1}{\sqrt 3}\)

2.

If sec θ – tan θ = M then sec θ + tan θ = \(\frac {1}{M}\).(a) False(b) TrueI got this question in a national level competition.My question comes from Trigonometric Identities in portion Trigonometry of Mathematics – Class 10

Answer» RIGHT option is (B) True

The explanation is: The appropriate TRIGONOMETRIC identity used here is SEC^2 θ – TAN^2 θ = 1.

(sec θ – tan θ) (sec θ + tan θ) = 1

M (sec θ + tan θ) = 1

(sec θ + tan θ) = \(\frac {1}{M}\)
3.

Evaluate sec^2 A + (1 + tan A) (1 – tan A).(a) 3(b) 0(c) 2(d) 1I had been asked this question in semester exam.My question is taken from Trigonometric Identities in portion Trigonometry of Mathematics – Class 10

Answer»

Correct CHOICE is (C) 2

For explanation I WOULD say: sec^2 A + (1 + TAN A) (1 – tan A) = sec^2 A + 1^2 – tan^2 A

= (sec^2 A – tan^2 A) + 1

= 1 + 1

= 2

4.

What is the value of cos (30° + 60°)?(a) 1(b) \(\frac {1}{4}\)(c) \(\frac {3}{4}\)(d) 0This question was addressed to me during an interview.My doubt is from Trigonometric Ratios of Specific Angles in chapter Trigonometry of Mathematics – Class 10

Answer»

The CORRECT choice is (a) 1

For explanation I would say: COS (30° + 60°) = cos (90°) = 1

The VALUE of cos (90°) is 1

5.

If the length of the side opposite to angle A is 15 units and the length of the hypotenuse is 17 units then the length of the side adjacent to angle A is _____(a) 8 units(b) 7 units(c) 4 units(d) 5 unitsThe question was posed to me during an interview.My question comes from Trigonometric Ratios topic in section Trigonometry of Mathematics – Class 10

Answer»

Right choice is (a) 8 UNITS

To explain: From PYTHAGORAS theorem, (Hypotenuse)^2 = (OPPOSITE side)^2 + (Adjacent side)^2

(Adjacent side)^2 = (Hypotenuse)^2 – (Opposite side)^2

Adjacent side = \(\sqrt {289225}\) = 8 units

6.

What is the value of sec θ when θ is 45°?(a) √3(b) 1(c) 0(d) √2The question was asked during a job interview.Enquiry is from Trigonometric Ratios of Specific Angles in chapter Trigonometry of Mathematics – Class 10

Answer» RIGHT choice is (d) √2

Explanation: The VALUE of cos 45° is \(\frac {1}{\sqrt 2}\) and secant is inverse to cos.

So, sec θ = \(\frac {1}{cos \, \THETA } = \frac {1}{1/\sqrt 2}\)

= √2
7.

Sec θ – \(\frac {1}{sec \, \theta }\) is _____(a) Tan θ / Sec ⁡θ(b) Tan^2 θ / Sec ⁡θ(c) Tan θ / Sec^2 ⁡θ(d) Sec⁡ θ / Tan ⁡θThis question was posed to me during an online exam.My question comes from Trigonometric Identities topic in section Trigonometry of Mathematics – Class 10

Answer»

Correct option is (b) Tan^2 θ / SEC ⁡θ

The EXPLANATION is: Sec θ – \(\frac {1}{sec \, \theta } = \frac {1}{sec \, \theta }\)(Sec^2 θ – 1)

= \(\frac {1}{sec \, \theta }\)(Tan^2 θ)

= Tan^2 θ / Sec ⁡θ

8.

If sin B = \(\frac {3}{5}\), then find sec B.(a) \(\frac {3}{4}\)(b) \(\frac {4}{5}\)(c) \(\frac {5}{4}\)(d) \(\frac {5}{3}\)I have been asked this question in an interview for job.The doubt is from Trigonometric Ratios in division Trigonometry of Mathematics – Class 10

Answer»

Correct option is (c) \(\FRAC {5}{4}\)

The explanation: SIN B = \(\frac {Opposite \, side}{Hypotenuse} = \frac {3}{5}\)

From Pythagoras theorem, (Hypotenuse)^2 = (Opposite side)^2 + (Adjacent side)^2

5^2 = 3^2 + (Adjacent side)^2

(Adjacent side)^2 = 5^2 – 3^2

Adjacent side = √16 = 4

Sec B = \(\frac {Hypotenuse}{Adjacent \, side} = \frac {5}{4}\)

9.

Which trigonometric ratios are positive in the fourth quadrant?(a) Cos, Sin(b) Sec, Cos(c) Sin, Cot(d) Tan, CotThe question was asked in a job interview.This key question is from Trigonometric Ratios of Complementary Angles in section Trigonometry of Mathematics – Class 10

Answer»

The correct answer is (B) SEC, Cos

The best I can EXPLAIN: A plane is divided into four INFINITE quadrants. The trigonometric ratios that are positive in the fourth quadrant are secant, COSINE and the rest of all trigonometric ratios are negative in this quadrant.

10.

Evaluate (cosec θ – cot θ) (cosec θ – cot θ).(a) 0(b) 1(c) 2(d) 3I got this question in an online interview.My doubt stems from Trigonometric Identities topic in section Trigonometry of Mathematics – Class 10

Answer»

The correct CHOICE is (B) 1

The EXPLANATION: (cosec θ – cot θ) (cosec θ – cot θ) = cosec^2θ – cot^2θ

= 1

The identity used here is cosec^2θ – cot^2θ = 1

11.

Which among these are complementary angles?(a) ∠A + ∠B = 90°(b) ∠A + ∠B = 180°(c) ∠A + ∠B = 60°(d) ∠A + ∠B = 45°This question was posed to me during an online interview.This question is from Trigonometric Ratios of Complementary Angles in portion Trigonometry of Mathematics – Class 10

Answer» RIGHT choice is (a) ∠A + ∠B = 90°

Easiest EXPLANATION: TWO ANGLES are SAID to be complementary angles if the sum of these two angles is 90° but if the sum of these two angles is 180° then these two angles are said to be supplementary.
12.

If cos θ = \(\frac {3}{4}\) then value of cos 2θ is ___________(a) \(\frac {1}{6}\)(b) \(\frac {1}{4}\)(c) \(\frac {1}{8}\)(d) \(\frac {3}{8}\)This question was addressed to me in semester exam.My doubt is from Trigonometric Ratios in chapter Trigonometry of Mathematics – Class 10

Answer»

Right option is (C) \(\frac {1}{8}\)

BEST explanation: COS 2θ = 2cos θ^2 – 1

cos θ = \(\frac {3}{4}\)

cos 2θ = 2(\(\frac {3}{4}\))^2 – 1

= \(\frac {1}{8}\)

13.

(1 + cosec⁡ θ) (1 – cosec⁡ θ) + cot^2⁡ θ is _____(a) Cot ⁡θ(b) 0(c) 1(d) Tan ⁡θI have been asked this question during a job interview.I would like to ask this question from Trigonometric Identities in portion Trigonometry of Mathematics – Class 10

Answer»

Correct answer is (B) 0

For EXPLANATION: (1 + cosec⁡ θ) (1 – cosec θ) + cot^2 ⁡θ = (1 – cosec^2 θ) + cot^2 θ

= -cot^2⁡ θ + cot^2⁡ θ(∵ cosec^2 A – cot^2 A = 1)

= 0

14.

The sum of two angles in ∆PQR is complementary with the right angle at Q.(a) True(b) FalseThe question was posed to me in an interview for job.The origin of the question is Trigonometric Ratios of Complementary Angles in chapter Trigonometry of Mathematics – Class 10

Answer»

The correct answer is (a) True

The BEST explanation: ∠P + ∠Q + ∠R = 180° ( ∵ The SUM of angles in a triangle is 180°)

∠P + 90° + ∠R = 180°

∠P + ∠R = 180° – 90°

∠P + ∠R = 90°

Two angles are SAID to be complementary angles if the sum of these two angles is 90°.

15.

Evaluate (sec θ – tan θ) (sec θ + tan θ).(a) 0(b) 1(c) 2(d) 3This question was posed to me in a job interview.Query is from Trigonometric Identities in chapter Trigonometry of Mathematics – Class 10

Answer»

The correct choice is (b) 1

Explanation: = (SEC θ – TAN θ) (sec θ + tan θ) = sec^2 θ – tan^2 θ

= 1

The identity USED here is sec^2 θ – tan^2 θ = 1

16.

The value of sin 90° + cos 0° + √2 cos 45° is_____(a) 2(b) 1(c) 4(d) 3I got this question in an internship interview.I'd like to ask this question from Trigonometric Ratios of Specific Angles topic in portion Trigonometry of Mathematics – Class 10

Answer»

Correct CHOICE is (d) 3

Best explanation: SIN 90° + cos 0° + √2 cos 45° = 1 + 1 + √2 (\(\frac {1}{\SQRT {2}}\))

= 1 + 1 + 1

= 3

17.

The value of each of the trigonometric ratios of an angle depends on the size of the triangle and does not depend on the angle.(a) True(b) FalseThis question was addressed to me during an online interview.I need to ask this question from Trigonometric Ratios in division Trigonometry of Mathematics – Class 10

Answer»

Right option is (b) False

Explanation: Consider, two triangles ABC and DEF

In ∆ABC,

sin B = \(\frac {AC}{AB} = \frac {10}{20} = \frac {1}{2}\) i.e. B = 30°

Now, in ∆DEF,

sin F = \(\frac {DE}{DF} = \frac {20}{40} = \frac {1}{2}\)i.e. F = 30°

From these examples it is evident that the VALUE of the trigonometric RATIOS depends on their angle and not on their lengths.

18.

Evaluate cos 30° sin 60° + cos 60° sin 30°.(a) 2(b) 0(c) 1(d) ∞I have been asked this question in class test.The above asked question is from Trigonometric Ratios of Specific Angles topic in portion Trigonometry of Mathematics – Class 10

Answer» RIGHT choice is (c) 1

The EXPLANATION: cos 30° sin 60° + cos 60° sin 30° = \(\frac {\SQRT 3}{2} . \frac {\sqrt {3}}{2} + \frac {1}{2} . \frac {1}{2}\)

= \(\frac {3 + 1}{4}\)

= \(\frac {4}{4}\)

= 1
19.

If sin (A + B) = \(\frac {\sqrt {3}}{2}\) and tan (A – B) = 1. What are the values of A and B?(a) 37, 54(b) 35.7, 40.7(c) 50, 10(d) 52.5, 7.5This question was addressed to me during an online exam.I'm obligated to ask this question of Trigonometric Ratios in section Trigonometry of Mathematics – Class 10

Answer» CORRECT option is (d) 52.5, 7.5

Explanation: The value of sin (A + B) = \(\frac {\sqrt {3}}{2}\) and sin 60° = \(\frac {\sqrt {3}}{2}\)

∴ A + B = 60(1)

The value of TAN (A – B) = 1 and tan 45° = 1

∴ A – B = 45(2)

Adding equation (1) and (2)

A + B = 60

+ A – B = 45

– – – – – – – – – – – – –

2 A = 105

A = 52.5

∴ B = 7.5
20.

Sec^2 θ – Sec^4 θ equals to _____(a) –Sec^2 θ Tan^2 θ(b) – Sec^2 θ Tan^2 θ(c) 1(d) 0This question was posed to me during an online exam.I'm obligated to ask this question of Trigonometric Identities topic in division Trigonometry of Mathematics – Class 10

Answer» RIGHT ANSWER is (a) –Sec^2 θ Tan^2 θ

The EXPLANATION: Sec^2 θ – Sec^4 θ = Sec^2 θ (1 – Sec^2 θ) (∵ sec^2 θ – tan^2 θ = 1)

= Sec^2 θ (-Tan^2 θ)

= -Sec^2 θ Tan^2 θ
21.

Find the distance between (sin θ, 0) and (0, cos θ).(a) 0(b) 1(c) \(\frac {4}{3} \)(d) \(\frac {3}{4} \)I have been asked this question by my school teacher while I was bunking the class.Origin of the question is Trigonometric Identities topic in section Trigonometry of Mathematics – Class 10

Answer»

Correct answer is (b) 1

Easy explanation: Let (X1, y1) = (sin θ, 0) and (x2, y2) = (0, COS θ)

Distance between TWO points = √((x2 – x1)^2 + (y2 – y1)^2)

= √((0 – sin θ)^2 + (cos θ – 0)^2)

= √(sin^2 θ + cos^2 θ)

= √1

= 1

22.

If tan A = \(\frac {89}{17}\), then cot A is _____(a) \(\frac {89}{17}\)(b) \(\frac {89}{16}\)(c) \(\frac {17}{89}\)(d) \(\frac {16}{89}\)This question was posed to me by my school teacher while I was bunking the class.This is a very interesting question from Trigonometric Ratios in chapter Trigonometry of Mathematics – Class 10

Answer»

Right choice is (c) \(\frac {17}{89}\)

The explanation is: Tan A and cot A are RECIPROCAL ratios and cot is INVERSE of tan.

Tan A = \(\frac {1}{Cot A} = \frac {1}{89/17}\)

= \(\frac {17}{89}\)

23.

\( \frac {1 – cot \, 45^{\circ}}{1+ cot \, 45^{\circ}}\) is _____(a) 0(b) 2(c) 3(d) 1This question was posed to me in exam.The origin of the question is Trigonometric Ratios ofSpecific Angles in division Trigonometry of Mathematics – Class 10

Answer»

The correct CHOICE is (a) 0

The best I can explain: \( \FRAC {1COT \, 45^{\circ}}{1+cot \, 45^{\circ}} = \frac {1-1}{1+1}\)

= \( \frac {0}{1}\)

= 0

24.

What is the value of\(\frac {2 cot \, ⁡60^{\circ }}{1 + cot \, ⁡⁡45^{\circ }}\)?(a) Cot 30°(b) Cot 45°(c) Cot 60°(d) Tan 60°I got this question during an interview for a job.My query is from Trigonometric Ratios of Specific Angles topic in portion Trigonometry of Mathematics – Class 10

Answer»

The CORRECT option is (c) COT 60°

The best explanation: \(\frac {2 cot \, ⁡⁡60^{\circ }}{1 + cot \, ⁡⁡45^{\circ }} = \frac {2 (\frac {1}{\sqrt 3})}{1 + 1}\)

= \(\frac {\frac {2}{\sqrt {3}}}{2}\)

= \(\frac {1}{\sqrt 3}\)

= Cot 60°

25.

If sin A = \(\frac {3}{5}\), then find tan A.(a) \(\frac {3}{4}\)(b) \(\frac {3}{5}\)(c) \(\frac {5}{3}\)(d) \(\frac {4}{3}\)This question was posed to me by my college director while I was bunking the class.I need to ask this question from Trigonometric Ratios topic in section Trigonometry of Mathematics – Class 10

Answer»

Right option is (a) \(\frac {3}{4}\)

EASY EXPLANATION: SIN A = \(\frac {OPPOSITE \, side}{Hypotenuse} = \frac {3}{5}\)

From Pythagoras theorem, (Hypotenuse)^2 = (Opposite side)^2 + (Adjacent side)^2

5^2 = 3^2 + (Adjacent side)^2

(Adjacent side)^2 = 5^2 – 3^2

Adjacent side = √16 = 4

Tan A = \(\frac {Opposite \, side}{Adjacent \, side} = \frac {3}{4}\)

26.

Choose the correct reciprocal ratios.(a) Tan θ, Sec θ(b) Cosec θ, Sec θ(c) Sec θ, Sin θ(d) Tan θ, Cot θThis question was addressed to me during an interview.I'd like to ask this question from Trigonometric Ratios topic in portion Trigonometry of Mathematics – Class 10

Answer»

Right OPTION is (d) Tan θ, Cot θ

To explain: Tan θ, Cot θ are the RECIPROCAL ratios because they are INVERSE to each other.

Tanθ = \(\frac {1}{Cot \theta }\)

27.

Evaluate (cosec^2 θ – cot^2 θ)^2 . (cosec θ + cot θ)^2.(a) 1(b) 0(c) (cosec^2 θ – cot^2 θ)^2(d) (cosec θ + cot θ)^2I had been asked this question in final exam.My question comes from Trigonometric Identities topic in chapter Trigonometry of Mathematics – Class 10

Answer» RIGHT choice is (d) (COSEC θ + COT θ)^2

Best explanation: (cosec^2 θ – cot^2 θ)^2 . (cosec θ + cot θ)^2 = 1 (cosec θ + cot θ)^2

= (cosec θ + cot θ)^2
28.

If the length of the opposite side is 20 units and the length of the hypotenuse is 29 units then find cosec A?(a) \(\frac {20}{29}\)(b) \(\frac {29}{21}\)(c) \(\frac {21}{20}\)(d) \(\frac {29}{20}\)I had been asked this question in exam.Question is from Trigonometric Ratios in portion Trigonometry of Mathematics – Class 10

Answer» CORRECT choice is (d) \(\frac {29}{20}\)

The best explanation: COSEC A = \(\frac {Length \, of \, the \, hypotenuse}{Length \, of \, the \, OPPOSITE \, side}\)

= \(\frac {29}{20}\)
29.

Evaluate cosec θ sec θ.(a) cos θ + tan θ(b) cos θ – tan θ(c) tan θ – cot θ(d) cot θ + tan θI have been asked this question in final exam.Asked question is from Trigonometric Identities in section Trigonometry of Mathematics – Class 10

Answer» RIGHT choice is (d) cot θ + tan θ

The explanation: COSEC θ sec θ = \(\frac {1}{SIN \, \theta } \frac {1}{COS \, \theta } \)

= \(\frac {1}{sin \, \theta \, cos \, \theta } \)(cos^2θ + sin^2θ)

= \(\frac {cos \, \theta }{sin \, \theta } + \frac {sin \, \theta }{cos \, \theta } \)

= cot θ + tan θ
30.

The meaning of the word trigonometry is three angles measure.(a) True(b) FalseThis question was posed to me in unit test.My question is taken from Trigonometric Ratios topic in chapter Trigonometry of Mathematics – Class 10

Answer»

Correct CHOICE is (a) True

To explain I would say: The word TRIGONOMETRY is from the language Greek where ‘TRI’ means three and ‘Goria’ means ‘angle’ and ‘Metron’ means measure which gives the MEANING as three ANGLES measure.

31.

The basic trigonometric ratios are _____(a) sine(b) tangent(c) sine, cosine and tangent(d) cosineThe question was asked during an interview.I need to ask this question from Trigonometric Ratios topic in division Trigonometry of Mathematics – Class 10

Answer»

Correct answer is (C) sine, cosine and tangent

To ELABORATE: The BASIC trigonometric RATIOS are sine, cosine and tangent and the other three trigonometric ratios secant, cosecant, cotangent are derived from these basic trigonometric ratios.

32.

Find the correct trigonometric identity.(a) cos^2 θ = 1 – sin^2 θ(b) cos^2 θ = 1 + sin^2 θ(c) tan^2 θ + sec^2 θ = 1(d) tan^2 θ = sec^2 θ + 1This question was posed to me in final exam.This key question is from Trigonometric Identities in section Trigonometry of Mathematics – Class 10

Answer»

Correct ANSWER is (a) cos^2 θ = 1 – sin^2 θ

The explanation is: The APPROPRIATE TRIGONOMETRIC identity used here is sin^2 θ + cos^2 θ = 1.

cos^2 θ = 1 – sin^2 θ

33.

What is the inverse of cosecant?(a) Cosine(b) Secant(c) Sine(d) TangentThis question was addressed to me in an online interview.I'd like to ask this question from Trigonometric Ratios topic in portion Trigonometry of Mathematics – Class 10

Answer»

The correct answer is (c) Sine

Easiest explanation: The INVERSE of cosecant is sine.

Cosec θ = \(\frac {1}{SIN \THETA }\)

34.

Evaluate sec 65° + cosec 75°.(a) Cosec 25° + Sec 15°(b) Cosec 25° – Sec 15°(c) Cosec 15° + Sec 25°(d) Cosec 15° – Sec 25°I got this question by my college professor while I was bunking the class.The origin of the question is Trigonometric Ratios of Complementary Angles in portion Trigonometry of Mathematics – Class 10

Answer»

The correct CHOICE is (C) Cosec 15° + Sec 25°

Best EXPLANATION: Sec 65° + Cosec 75° = Sec (90° – 25°) + Cosec (90° – 15°)

= Cosec 25° + sec 15°

35.

What is the value of sec 60° – \( \frac {1}{cosec \, 90^{\circ }}\)?(a) Cot 30°(b) Cot 45°(c) Cot 60°(d) Tan 60°The question was asked during an internship interview.This question is from Trigonometric Ratios ofSpecific Angles topic in chapter Trigonometry of Mathematics – Class 10

Answer»

Right CHOICE is (b) COT 45°

Explanation: sec 60° – \( \frac {1}{cosec \, 90^{\CIRC }}\) = 2 – \( \frac {1}{1}\)

= 1

= cot 45°

36.

What is the value of tan θ when θ is 30°?(a) \( \frac {1}{\sqrt 3}\)(b) 1(c) 0(d) 2I got this question by my college professor while I was bunking the class.Enquiry is from Trigonometric Ratios ofSpecific Angles in portion Trigonometry of Mathematics – Class 10

Answer»

The correct option is (a) \( \frac {1}{\sqrt 3}\)

The explanation: Tan θ = \( \frac {SIN \, \THETA}{Cos \, \theta} = \frac {Sin \, 30^{\circ }}{Cos \, 30^{\circ }} \)

= \( \frac {1/2}{\sqrt 3/2}\)

= \( \frac {1}{2} \times \frac {2}{\sqrt 3}\)

= \( \frac {1}{\sqrt 3}\)

37.

What is the value of sin30°cos15° + cos30°sin15°?(a) \(\frac {1}{2}\)(b) 0(c) 1(d) \(\frac {1}{\sqrt {2}}\)I have been asked this question in quiz.Origin of the question is Trigonometric Ratios in section Trigonometry of Mathematics – Class 10

Answer»

The correct ANSWER is (d) \(\FRAC {1}{\SQRT {2}}\)

For EXPLANATION: sin30°cos15° + cos30°sin15° = sin⁡45° = \(\frac {1}{\sqrt {2}}\)

38.

An identity is an equation.(a) False(b) TrueThis question was addressed to me during an online interview.My question comes from Trigonometric Identities topic in portion Trigonometry of Mathematics – Class 10

Answer»

Right ANSWER is (b) True

The best explanation: YES, an equation is an identity. If this identity is true for all VALUES of the variables in an equation. For example (a – b)^2 = a^2 + b^2 – 2ab is an identity.

39.

Evaluate \(\frac {1+cos \, \theta }{sin \, \theta } \)(cosec θ – cot θ).(a) cosec θ + cot θ(b) cot^2 θ + tan^2 θ(c) cot θ – tan θ(d) cosec^2 θ – cot^2 θThe question was asked in quiz.My doubt stems from Trigonometric Identities in section Trigonometry of Mathematics – Class 10

Answer» CORRECT choice is (d) cosec^2 θ – cot^2 θ

To EXPLAIN I would SAY: \(\frac {1+cos \, \THETA }{sin \, \theta } \)(cosec θ – cot θ) = \(\frac {1}{sin \, \theta }+ \frac {cos \, \theta }{sin \, \theta } \)(cosec θ – cot θ)

= (cosec θ + cot θ)(cosec θ – cot θ)

= cosec^2 θ – cot^2 θ
40.

Which trigonometric ratios are positive in the second quadrant?(a) Cosec, Sin(b) Sec, Tan(c) Sin, Cot(d) Tan, CotThis question was addressed to me during an online interview.I'd like to ask this question from Trigonometric Ratios of Complementary Angles in portion Trigonometry of Mathematics – Class 10

Answer»

Right choice is (a) Cosec, Sin

The EXPLANATION is: A plane is DIVIDED into four infinite quadrants. The TRIGONOMETRIC ratios that are positive in the SECOND quadrant are sine, cosecant and the rest of all trigonometric ratios are NEGATIVE in this quadrant.

41.

Cosec 0° is _____(a) Not defined(b) 1(c) 0(d) 2I have been asked this question in class test.This intriguing question comes from Trigonometric Ratios of Specific Angles in portion Trigonometry of Mathematics – Class 10

Answer» CORRECT choice is (a) Not defined

Easiest explanation: COSEC 0° = \(\frac {1}{Sin \, ⁡0^{\circ } } = \frac {1}{0}\)

Any NUMBER DIVIDED with 0 is always not defined.
42.

The product of sin θ and Cosec θ is 1.(a) True(b) FalseThis question was posed to me in an interview.Question is from Trigonometric Ratios topic in chapter Trigonometry of Mathematics – Class 10

Answer»

Right ANSWER is (a) True

Easiest EXPLANATION: The inverse of cosecant is sine.

Sin θ = \(\FRAC {1}{COSEC \THETA }\)

Sin θ.Cosec θ = 1

43.

In triangle ABC, right angled at C, then the value of cosec (A + B) is __________(a) 2(b) 0(c) 1(d) ∞This question was addressed to me in quiz.This intriguing question comes from Trigonometric Ratios topic in chapter Trigonometry of Mathematics – Class 10

Answer»

The correct answer is (c) 1

The best explanation: Since the triangle is right angles at C,

The SUM of the remaining TWO angles will be 90

∴ cosec(A + B) = Cosec 90° = 1

44.

If tan α = √3 and cosec β = 1, then the value of α – β?(a) -30°(b) 30°(c) 90°(d) 60°The question was posed to me in an interview.This interesting question is from Trigonometric Ratios topic in portion Trigonometry of Mathematics – Class 10

Answer» CORRECT CHOICE is (a) -30°

Easiest explanation: TAN α = √3 and tan 60° = √3

∴ α = 60°

Cosec β = 1 and cosec 90° = 1

∴β = 90°

α – β = 60 – 90 = -30°
45.

Cot(180° – a) is _____(a) sine of angle A(b) -cosec of angle A(c) tan of angle A(d) -cot of angle AThis question was posed to me in quiz.The doubt is from Trigonometric Ratios of Complementary Angles topic in division Trigonometry of Mathematics – Class 10

Answer»

The correct ANSWER is (b) -cosec of angle A

The best I can explain: (180° – a) refers to the SECOND quadrant which LIES in the range from 90° to 180°. Trigonometric ratios SINE and cosec are only positive in the second quadrant and remaining all the trigonometric ratios are negative.

So, Cot (180° – a) = -Cot A

46.

Sin (90° – x) equals to ______(a) cos x(b) cot x(c) cosec x(d) sec xThe question was asked in quiz.Query is from Trigonometric Ratios of Complementary Angles topic in portion Trigonometry of Mathematics – Class 10

Answer»

Right ANSWER is (a) COS x

The best I can explain: (90° – x) refers to the first QUADRANT which lies in the range from 0° to 90°. All trigonometric RATIOS are POSITIVE in the first quadrant and sine changes to cosine when it is 90° or 270°.

47.

The value of sin^2 90° + √2 cos 45° + √3 cot 30° is_____(a) 2(b) 0(c) 4(d) 5This question was posed to me in unit test.I want to ask this question from Trigonometric Ratios ofSpecific Angles in chapter Trigonometry of Mathematics – Class 10

Answer» CORRECT option is (d) 5

Explanation: sin^2 90° + √2 cos 45° + √3 cot 30° = 1^2 + √2 (\( \frac {1}{\SQRT 2}\))+ √3 (√3)

= 1 + 1 + 3

= 5
48.

\(\frac {Length \, of \, hypotenuse}{Length \, of \, opposite \, to \, angle \, A}\) is _____(a) sine of angle A(b) cosec of angle A(c) tan of angle A(d) cot of angle AI had been asked this question in an online quiz.This interesting question is from Trigonometric Ratios topic in chapter Trigonometry of Mathematics – Class 10

Answer» CORRECT choice is (b) cosec of angle A

Easy explanation: The formula for cosec A is \(\frac {Length \, of \, HYPOTENUSE \, of \, the \, triangle}{Length \, of \, opposite \, SIDE \, to \, angle \, A}\).
49.

Who is the ‘Father of Trigonometry’?(a) Hipparchus(b) Euclid(c) Aristotle(d) ArchimedesI have been asked this question in an international level competition.The doubt is from Trigonometric Ratios in section Trigonometry of Mathematics – Class 10

Answer»

The correct CHOICE is (a) Hipparchus

Easiest explanation: Hipparchus was a Greek mathematician and is considered as the ‘Father of TRIGONOMETRY’. Hipparchus not only contributed to MATHEMATICS but also to ASTRONOMY.

50.

\(\frac {Sin \theta }{Cos \theta}\) equals to ______(a) tan θ(b) cot θ(c) cosec θ(d) sec θThe question was asked in homework.My question is from Trigonometric Ratios in section Trigonometry of Mathematics – Class 10

Answer»

Correct answer is (a) TAN θ

For explanation I would say: SIN θ = \(\frac {Length \, of \, opposite \, side \, of \, the \, triangle}{Length \, of \, HYPOTENUSE \, of \, the \, triangle}\)

Cos θ = \(\frac {Length \, of \, adjacent \, side \, of \, the \, triangle}{Length \, of \, hypotenuse \, of \, the \, triangle}\)

\(\frac {Sin \THETA }{Cos \theta} = \frac {Length \, of \, opposite \, side \, of \, the \, triangle}{Length \, of \, adjacent \, of \, the \, triangle}\)

= Tan θ