If sin A = \(\frac {3}{5}\), then find tan A.(a) \(\frac {3}{4}\)(b) \(\frac {3}{5}\)(c) \(\frac {5}{3}\)(d) \(\frac {4}{3}\)This question was posed to me by my college director while I was bunking the class.I need to ask this question from Trigonometric Ratios topic in section Trigonometry of Mathematics – Class 10

If sin A = \(\frac {3}{5}\), then find tan A.(a) \(\frac {3}{4}\)(b) \

1.	If sin A = \(\frac {3}{5}\), then find tan A.(a) \(\frac {3}{4}\)(b) \(\frac {3}{5}\)(c) \(\frac {5}{3}\)(d) \(\frac {4}{3}\)This question was posed to me by my college director while I was bunking the class.I need to ask this question from Trigonometric Ratios topic in section Trigonometry of Mathematics – Class 10
Answer» Right option is (a) \(\frac {3}{4}\) EASY EXPLANATION: SIN A = \(\frac {OPPOSITE \, side}{Hypotenuse} = \frac {3}{5}\) From Pythagoras theorem, (Hypotenuse)^2 = (Opposite side)^2 + (Adjacent side)^2 5^2 = 3^2 + (Adjacent side)^2 (Adjacent side)^2 = 5^2 – 3^2 Adjacent side = √16 = 4 Tan A = \(\frac {Opposite \, side}{Adjacent \, side} = \frac {3}{4}\)

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