If sec θ – tan θ = M then sec θ + tan θ = \(\frac {1}{M}\).(a) False(b) TrueI got this question in a national level competition.My question comes from Trigonometric Identities in portion Trigonometry of Mathematics – Class 10

If sec θ – tan θ = M then sec θ + tan θ = \(\frac {1}{M}\).(a) F

1.	If sec θ – tan θ = M then sec θ + tan θ = \(\frac {1}{M}\).(a) False(b) TrueI got this question in a national level competition.My question comes from Trigonometric Identities in portion Trigonometry of Mathematics – Class 10
Answer» RIGHT option is (B) True The explanation is: The appropriate TRIGONOMETRIC identity used here is SEC^2 θ – TAN^2 θ = 1. (sec θ – tan θ) (sec θ + tan θ) = 1 M (sec θ + tan θ) = 1 (sec θ + tan θ) = \(\frac {1}{M}\)

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