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If sin B = \(\frac {3}{5}\), then find sec B.(a) \(\frac {3}{4}\)(b) \(\frac {4}{5}\)(c) \(\frac {5}{4}\)(d) \(\frac {5}{3}\)I have been asked this question in an interview for job.The doubt is from Trigonometric Ratios in division Trigonometry of Mathematics – Class 10

Answer»

Correct option is (c) \(\FRAC {5}{4}\)

The explanation: SIN B = \(\frac {Opposite \, side}{Hypotenuse} = \frac {3}{5}\)

From Pythagoras theorem, (Hypotenuse)^2 = (Opposite side)^2 + (Adjacent side)^2

5^2 = 3^2 + (Adjacent side)^2

(Adjacent side)^2 = 5^2 – 3^2

Adjacent side = √16 = 4

Sec B = \(\frac {Hypotenuse}{Adjacent \, side} = \frac {5}{4}\)



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