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If tan A = \(\frac {89}{17}\), then cot A is _____(a) \(\frac {89}{17}\)(b) \(\frac {89}{16}\)(c) \(\frac {17}{89}\)(d) \(\frac {16}{89}\)This question was posed to me by my school teacher while I was bunking the class.This is a very interesting question from Trigonometric Ratios in chapter Trigonometry of Mathematics – Class 10

Answer»

Right choice is (c) \(\frac {17}{89}\)

The explanation is: Tan A and cot A are RECIPROCAL ratios and cot is INVERSE of tan.

Tan A = \(\frac {1}{Cot A} = \frac {1}{89/17}\)

= \(\frac {17}{89}\)



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