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The value of sin 90° + cos 0° + √2 cos 45° is_____(a) 2(b) 1(c) 4(d) 3I got this question in an internship interview.I'd like to ask this question from Trigonometric Ratios of Specific Angles topic in portion Trigonometry of Mathematics – Class 10

Answer»

Correct CHOICE is (d) 3

Best explanation: SIN 90° + cos 0° + √2 cos 45° = 1 + 1 + √2 (\(\frac {1}{\SQRT {2}}\))

= 1 + 1 + 1

= 3



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