89 + Interview Questions in Trigonometry in Mathematics

51.	Evaluate \(\sqrt {\frac {1 – sin⁡ \, ⁡A}{1 + sin \, ⁡⁡A}}\).(a) cos A + tan A(b) cos A – tan A(c) tan A – cot A(d) sec A + tan AThis question was posed to me in unit test.This intriguing question comes from Trigonometric Identities in section Trigonometry of Mathematics – Class 10
Answer» CORRECT option is (d) sec A + TAN A Best explanation: \(\SQRT {\frac {1 – sin⁡ \, ⁡A}{1 + sin⁡ \, ⁡A}} = \sqrt {\frac {1 – sin⁡ \, ⁡A}{1 + sin \, ⁡⁡A}} . \sqrt {\frac {1 – sin \, ⁡A}{1 – sin \, ⁡⁡A}}\) = \(\frac {\sqrt {(1 + sin \, ⁡A)^2}}{\sqrt {1 – sin^2} \, ⁡A} \) = \(\frac {1 + sin⁡ \, ⁡A}{\sqrt {cos^2} \, ⁡A}\)(&because; sin^2 A + cos^2 A = 1) = \(\frac {1 + sin⁡ \, ⁡A}{cos⁡ \, ⁡A}\) = sec A + tan A

Discussion

52.	What is the product of cot 42° and tan 48°?(a) Cot^2 42°(b) Tan^2 42°(c) 2Tan 16°(d) 2Cot 16°The question was asked in an online interview.I need to ask this question from Trigonometric Ratios of Complementary Angles in division Trigonometry of Mathematics – Class 10
Answer» RIGHT ANSWER is (a) COT^2 42° Best EXPLANATION: (Cot 42°) (TAN 48°) = (Cot 42°) Tan (90° – 42°) = Cot 42° Cot 42° = Cot^2 42°

Discussion

53.	Sec 75° equals to _____(a) cosec 15°(b) sec 15°(c) 1(d) 0I had been asked this question by my college professor while I was bunking the class.This is a very interesting question from Trigonometric Ratios of Complementary Angles topic in portion Trigonometry of Mathematics – Class 10
Answer» RIGHT answer is (a) COSEC 15° Explanation: All trigonometric ratios are positive in the first QUADRANT and secant changes to COSECANT when it is 90° or 270°. Sec 75° = Sec (90° – 15°) = Cosec 15°

Discussion

54.	What is the value of tan 48°?(a) Cot 42°(b) Tan 42°(c) Tan 16°(d) Cot 16°This question was posed to me by my college director while I was bunking the class.This is a very interesting question from Trigonometric Ratios of Complementary Angles topic in division Trigonometry of Mathematics – Class 10
Answer» Correct CHOICE is (a) COT 42° Best EXPLANATION: All trigonometric ratios are positive in the first quadrant and tan CHANGES to cot when it is 90° or 270°. Tan 48° = Tan (90° – 42°) = Cot 42°

Discussion

55.	Cosec 90° is _____(a) 0(b) 2(c) 1(d) √3I got this question in an interview for internship.I would like to ask this question from Trigonometric Ratios of Specific Angles topic in division Trigonometry of Mathematics – Class 10
Answer» The correct choice is (C) 1 Explanation: Cosec 90° = \(\FRAC {1}{SIN \, ⁡90^{\circ } }\) = \(\frac {1}{1}\) = 1

Discussion

56.	If cos C = \(\frac {8}{17}\) and sec C = \(\frac {17}{8}\), then 1 is the product of cos C and sec C.(a) False(b) TrueI got this question in final exam.My question is based upon Trigonometric Ratios topic in division Trigonometry of Mathematics – Class 10
Answer» Right option is (B) True Easy EXPLANATION: Cos and SINE are reciprocal trigonometric ratios. These TWO ratios are inverse to each other. Cos C = \(\frac {1}{Sec \, C}\) (Cos C)(Sec C) = 1 \((\frac {8}{17}) (\frac {17}{8})\) = 1

Discussion

57.	In a right angled triangle, the trigonometric function that is equal to the ratio of the side opposite a given angle to the hypotenuse is called cosine.(a) False(b) TrueI got this question in an online interview.I'm obligated to ask this question of Trigonometric Ratios in division Trigonometry of Mathematics – Class 10
Answer» CORRECT choice is (a) False To explain I WOULD SAY: In this ∆ ABC, SIN = \(\frac {OPPOSITE}{hypotenuse}\)

Discussion

58.	Find the value of tan 225°.(a) \(\frac {1}{\sqrt 2}\)(b) 1(c) -√2(d) \(\frac {-1}{\sqrt 2}\)I got this question in an online interview.This interesting question is from Trigonometric Ratios of Complementary Angles in section Trigonometry of Mathematics – Class 10
Answer» Correct CHOICE is (B) 1 For explanation: TAN 225° = Tan (180° + 45°) = Tan 45° = 1

Discussion

59.	Cot 405° equals to _____(a) cosec 15°(b) sec 15°(c) 1(d) 0The question was asked in exam.This question is from Trigonometric Ratios of Complementary Angles in portion Trigonometry of Mathematics – Class 10
Answer» The CORRECT choice is (c) 1 Explanation: All trigonometric RATIOS are positive in the FIRST quadrant. So, Cot 405° = Cot (360° + 45°) = Cot 45° = 1

Discussion

60.	The sum of two angles in ∆ABC is supplementary with the right angle at B.(a) False(b) TrueThe question was asked during an internship interview.This intriguing question comes from Trigonometric Ratios of Complementary Angles in portion Trigonometry of Mathematics – Class 10
Answer» Correct choice is (a) False For explanation: A triangle contains three ANGLES and their SUM should be EQUAL to 180° but the definition of supplementary angles says that two angles can be supplementary angles if the sum of these two angles is 180°.

Discussion

61.	If sin A = \(\frac {8}{17}\), what will be the value of cos A sec A?(a) 2(b) -1(c) 1(d) 0This question was posed to me by my college director while I was bunking the class.My doubt is from Trigonometric Ratios in section Trigonometry of Mathematics – Class 10
Answer» The correct option is (c) 1 Easy explanation: sin A = \(\FRAC {8}{17}\) COS A sec A can be written as cos⁡A × \(\frac {1}{sec⁡A}\) = 1 ∴ cos A sec A = 1

Discussion

62.	Trigonometry is also applicable to obtuse angles triangles.(a) True(b) FalseI have been asked this question in final exam.I'd like to ask this question from Trigonometric Ratios in portion Trigonometry of Mathematics – Class 10
Answer» Right OPTION is (b) False For explanation I would SAY: Trigonometry is only APPLICABLE to right – angled triangles WHOSE angle is 90° between two sides of a triangle and it gives the relation between the length of sides and angles of a right – angled triangle.

Discussion

63.	Sec (360° – θ) is _____(a) sine of angle θ(b) secant of angle θ(c) tan of angle θ(d) cot of angle θThis question was addressed to me during an interview.The question is from Trigonometric Ratios of Complementary Angles in section Trigonometry of Mathematics – Class 10
Answer» Right answer is (b) secant of ANGLE θ Explanation: (360° – θ) REFERS to the fourth quadrant which lies in the range from 270° to 360°. TRIGONOMETRIC ratios secant and COSINE are only POSITIVE in the second quadrant and remaining all the trigonometric ratios are negative. So, Sec (360° – θ) = Sec θ

Discussion

64.	Evaluate \(\frac {sin \, 54^{\circ }}{cos⁡ \, 36^{\circ }}\).(a) 0(b) 1(c) \(\frac {4}{3}\)(d) \(\frac {3}{4}\)I have been asked this question by my college professor while I was bunking the class.The above asked question is from Trigonometric Ratios of Complementary Angles topic in portion Trigonometry of Mathematics – Class 10
Answer» Correct option is (b) 1 Explanation: \(\FRAC {sin \, 54^{\circ }}{cos⁡ \, 36^{\circ }} = \frac {sin \, (90^{\circ }-36^{\circ })}{cos⁡ \, 36^{\circ }}\) = \(\frac {Cos \, 36^{\circ }}{Cos \, 36^{\circ }}\) = 1

Discussion

65.	Two angles are said to be supplementary if the sum of these two angles is 180°.(a) False(b) TrueI got this question by my school principal while I was bunking the class.This interesting question is from Trigonometric Ratios of Complementary Angles topic in portion Trigonometry of Mathematics – Class 10
Answer» CORRECT ANSWER is (b) True The best explanation: Two angles are SAID to be SUPPLEMENTARY angles if the sum of these two angles is 180° but if the sum of these two angles is 90° then these two angles are said to be COMPLEMENTARY.

Discussion

66.	\(\frac {Cos A}{Sin A}\) = ______(a) Tan A(b) Sin A(c) Cot A(d) Sec AThe question was posed to me in final exam.Asked question is from Trigonometric Ratios topic in division Trigonometry of Mathematics – Class 10
Answer» Right option is (C) Cot A For explanation I WOULD say: Sin A = \(\frac {LENGTH \, of \, the \, OPPOSITE \, side}{Length \, of \, the \, hypotenuse}\), Cos A = \(\frac {Length \, of \, the \, adjacent \, side}{Length \, of \, the \, hypotenuse}\) \(\frac {Cos A}{Sin A} = \frac {Length \, of \, the \, adjacent \, side}{Length \, of \, the \, opposite \, side}\) = Cot A

Discussion

67.	Trigonometric ratios are______(a) sine, cosine and cotangent(b) sine, tangent, cotangent and secant(c) sine, cosine, tangent, cotangent, secant and cosecant(d) tangent, cotangent and secantI got this question in a job interview.My query is from Trigonometric Ratios topic in portion Trigonometry of Mathematics – Class 10
Answer» Correct choice is (c) sine, COSINE, tangent, cotangent, secant and cosecant To explain I WOULD say: Trigonometric RATIOS are generally defined as the ratios of any two sides of a right-angled triangle and it GIVES the relation between sides of a right-angled triangle to its appropriate angle. Sine, cosine, tangent, cotangent, secant and cosecant are six trigonometric ratios used in TRIGONOMETRY.

Discussion

68.	If tan θ = \(\frac {3}{4}\) then the value of sinθ is _________(a) \(\frac {3}{5}\)(b) \(\frac {4}{4}\)(c) \(\frac {3}{4}\)(d) \(\frac {-3}{5}\)This question was posed to me during an interview.My question is from Trigonometric Ratios topic in portion Trigonometry of Mathematics – Class 10
Answer» Correct option is (a) \(\frac {3}{5}\) The best I can explain: tanθ = \(\frac {BC}{AC} = \frac {3}{4} = \frac {3k}{4k}\) HENCE, BC = 3k, AC = 4k Using Pythagoras theorem AB^2 = AC^2 + BC^2 AB^2 = 4k^2 + 3k^2 AB = 5k sinθ = \(\frac {BC}{AB} = \frac {3k}{5k} = \frac {3}{5}\)

Discussion

69.	Evaluate tan^2 A + (1 + sec A) (sec A – 1).(a) 3 tan^2 A(b) 0(c) 2tan^2 A(d) 1The question was posed to me during an online exam.My question comes from Trigonometric Identities topic in division Trigonometry of Mathematics – Class 10
Answer» CORRECT answer is (C) 2tan^2 A The explanation: tan^2 A + (1 + sec A) (sec A – 1) = tan^2 A + (sec A + 1) (sec A – 1) = tan^2 A + (sec^2 A – 1) = tan^2 A + tan^2 A = 2tan^2 A

Discussion

70.	(sin A – cos A)^2 is equal to _____(a) 1 + 2sin A cos A(b) 1 – 2sin A cos A(c) 2sin A cos A – 1(d) 2sin A cos A + 1I have been asked this question in semester exam.This interesting question is from Trigonometric Identities in chapter Trigonometry of Mathematics – Class 10
Answer» Correct option is (b) 1 – 2SIN A COS A The BEST explanation: (SIN A – cos A)^2 = sin^2 A + cos^2 A – 2sin A cos A = 1 – 2sin A cos A

Discussion

71.	Evaluate \(\frac {Cot \, 54^{\circ }}{tan \, ⁡36^{\circ }}\).(a) 0(b) 1(c) \(\frac {4}{3}\)(d) \(\frac {3}{4}\)The question was posed to me at a job interview.The above asked question is from Trigonometric Ratios of Complementary Angles topic in portion Trigonometry of Mathematics – Class 10
Answer» RIGHT option is (B) 1 The explanation: \(\frac {Cot \, 54^{\CIRC }}{tan⁡ \, 36^{\circ }} = \frac {Cot \, (90^{\circ }-36^{\circ })}{tan⁡ \, 36^{\circ }} \) = \(\frac {tan \, 36^{\circ }}{tan⁡ \, 36^{\circ }} \) = 1

Discussion

72.	What is the value of sec 0° + cosec 90°?(a) 0(b) 2(c) 1(d) ∞I had been asked this question during an interview for a job.The doubt is from Trigonometric Ratios ofSpecific Angles topic in section Trigonometry of Mathematics – Class 10
Answer» CORRECT answer is (B) 2 The explanation: The VALUE of sec 0° is 1 and the value of COSEC 90° is 1. sec 0° + cosec 90° = 1 + 1 = 2

Discussion

73.	60° lies in the_____ quadrant.(a) first(b) second(c) third(d) fourthThis question was posed to me during an online interview.This is a very interesting question from Trigonometric Ratios of Specific Angles topic in portion Trigonometry of Mathematics – Class 10
Answer» The correct choice is (a) FIRST The BEST explanation: A PLANE is divided into four quadrants. The first quadrant RANGES from 0° to 90°. So, 60° lies between 0° to 90° which is in the first quadrant of a plane.

Discussion

74.	What is the value of sin 0° + cos 0°?(a) 0(b) 2(c) 1(d) ∞I have been asked this question during an interview.This key question is from Trigonometric Ratios of Specific Angles topic in portion Trigonometry of Mathematics – Class 10
Answer» Correct option is (C) 1 The best I can explain: The VALUE of sin 0° is 0 and the value of COS 0° is 1. sin 0° + cos 0° = 0 + 1 = 1

Discussion

75.	What is the value of cos^2θ – sin^2θ if the length of the opposite side is 20 units and the length of the hypotenuse is 29 units?(a) \(\frac {- 41}{841}\)(b) \(\frac {- 41}{840}\)(c) \(\frac {41}{841}\)(d) \(\frac {41}{840}\)I have been asked this question in an interview.The question is from Trigonometric Ratios topic in portion Trigonometry of Mathematics – Class 10
Answer» CORRECT choice is (a) \(\FRAC {- 41}{841}\) The best explanation: From Pythagoras theorem, (Hypotenuse)^2 = (OPPOSITE side)^2 + (Adjacent side)^2 (Adjacent side)^2 = (Hypotenuse)^2 – (Opposite side)^2 Adjacent side = √441 = 21 Cosθ = \(\frac {Length \, of \, the \, adjacent \, side}{Length \, of \, the \, hypotenuse} = \frac {21}{29}\), Sinθ = \(\frac {Length \, of \, the \, opposite \, side}{Length \, of \, the \, hypotenuse} = \frac {20}{29} \) cos^2θ – sin^2θ = (\(\frac {21}{29}\))^2 + (\(\frac {20}{29} \))^2 = \(\frac {- 41}{841}\)

Discussion

76.	What is the cotangent of an angle θ if the side adjacent to θ is 8 units and the side opposite to θ is 3 units?(a) \(\frac {3}{8}\)(b) \(\frac {8}{3}\)(c) \(\frac {4}{3}\)(d) \(\frac {3}{4}\)This question was addressed to me during an internship interview.The origin of the question is Trigonometric Ratios topic in division Trigonometry of Mathematics – Class 10
Answer» The correct choice is (b) \(\frac {8}{3}\) To explain: COTANGENT θ = \(\frac {Length \, of \, adjacent \, SIDE \, of \, the \, triangle}{Length \, of \, OPPOSITE \, of \, the \, triangle}\) = \(\frac {8}{3}\)

Discussion

77.	What is the value of cos A sec A + sin A cosec A – tan A cot A?(a) 0(b) 2(c) 1(d) 3I got this question in an interview for internship.This interesting question is from Trigonometric Ratios topic in chapter Trigonometry of Mathematics – Class 10
Answer» Correct option is (C) 1 To EXPLAIN I would say: Cos A SEC A = 1 Similarly sin A COSEC A = 1 and tan A cot A = 1 ∴ cos A sec A + sin A cosec A – tan A cot A = 1 + 1 – 1 = 1

Discussion

78.	135° lies in the third quadrant.(a) True(b) FalseThis question was posed to me in a national level competition.I want to ask this question from Trigonometric Ratios ofSpecific Angles topic in chapter Trigonometry of Mathematics – Class 10
Answer» RIGHT CHOICE is (b) False Easy explanation: A plane is DIVIDED into four quadrants. The second quadrant ranges from 90° to 180°. So, 135° lies between 90° to 180° which is in the second quadrant of a plane not in the third quadrant.

Discussion

79.	Evaluate (cosec A – 1) (cosec A + 1) (sec^2 A – 1).(a) 0(b) 1(c) \(\frac {4}{3}\)(d) \(\frac {3}{4}\)The question was posed to me in an interview for job.I would like to ask this question from Trigonometric Identities topic in portion Trigonometry of Mathematics – Class 10
Answer» The correct answer is (B) 1 For explanation: (COSEC A – 1) (cosec A + 1) (sec^2 A – 1) = (cosec^2 A – 1) (sec^2 A – 1) = cot^2A . tan^2 A = \(\FRAC {1}{tan^2 A}\) . tan^2 A = 1

Discussion

80.	(1 – sin^2 A) (1 + tan^2 A) equals to _____(a) – Sec^2 θ Tan^2 θ(b) – Sec^2 θ Tan^2 θ(c) 1(d) 0I got this question during an interview.I'd like to ask this question from Trigonometric Identities in section Trigonometry of Mathematics – Class 10
Answer» RIGHT option is (c) 1 To ELABORATE: (1 – sin^2 A) (1 + tan^2 A) = cos^2 A . sec^2 A = cos^2 A . \(\frac {1}{cos^2 A}\) = 1

Discussion

81.	What is the value of cos 45° + sin 45°?(a) 1(b) \( \frac {1}{4}\)(c) \( \frac {3}{4}\)(d) √2The question was posed to me in unit test.I'm obligated to ask this question of Trigonometric Ratios ofSpecific Angles topic in division Trigonometry of Mathematics – Class 10
Answer» The correct option is (d) √2 Best explanation: COS 45° + SIN 45° = \( \frac {1}{\SQRT 2} + \frac {1}{\sqrt 2}\) = 2 × \( \frac {1}{\sqrt 2}\)( SINCE, 2 = √2 × √2 ) = √2

Discussion

82.	Evaluate sin^2 30.(a) 2(b) 0(c) \( \frac {1}{4}\)(d) ∞This question was posed to me in my homework.My doubt stems from Trigonometric Ratios ofSpecific Angles in portion Trigonometry of Mathematics – Class 10
Answer» The CORRECT answer is (C) \( \frac {1}{4}\) Easy explanation: Sin^2 30° = (\( \frac {1}{2}\))^2 = \( \frac {1}{4}\)

Discussion

83.	(sin A + cos A)^2 is equal to _____(a) 1 + 2sin A cos A(b) 1 – 2sin A cos A(c) 2sin A cos A – 1(d) 2sin A cos A + 1This question was addressed to me in an international level competition.The origin of the question is Trigonometric Identities in portion Trigonometry of Mathematics – Class 10
Answer» Correct OPTION is (a) 1 + 2sin A COS A Easiest EXPLANATION: (sin A + cos A)^2 = sin^2 A + cos^2 A + 2sin A cos A = 1 + 2sin A cos A

Discussion

84.	Sin (270° – x) equals to ______(a) -cos x(b) cot x(c) -cosec x(d) sec xThis question was addressed to me in final exam.The above asked question is from Trigonometric Ratios of Complementary Angles topic in portion Trigonometry of Mathematics – Class 10
Answer» Correct OPTION is (a) -cos x For explanation I would say: (270° – x) refers to the third QUADRANT which LIES in the RANGE from 90° to 270°. Tan and cot are only positive in the third quadrant and sine changes to COSINE when it is 90° or 270°. Sin (270° – x) = -Cos x

Discussion

85.	Evaluate tan 75° + cot 65°.(a) Cot 25° + Tan 15°(b) Cot 25° – Tan 15°(c) Cot 15° + Tan 25°(d) Cot 15° – Tan 25°This question was posed to me during a job interview.Question is taken from Trigonometric Ratios of Complementary Angles topic in division Trigonometry of Mathematics – Class 10
Answer» RIGHT option is (C) COT 15° + Tan 25° Easy EXPLANATION: Tan 75° + Cot 65° = Tan (90° – 15°) + Cot (90° – 25°) = Cot 15° + Tan 25°

Discussion

86.	Find the value of cos 135°.(a) \(\frac {1}{\sqrt {2}}\)(b) √2(c) -√2(d) \(\frac {-1}{\sqrt {2}}\)This question was addressed to me during a job interview.The query is from Trigonometric Ratios of Complementary Angles in division Trigonometry of Mathematics – Class 10
Answer» CORRECT option is (d) \(\frac {-1}{\SQRT {2}}\) Explanation: COS 135° = Cos (90° + 45°) = -Sin 45° = \(\frac {-1}{\sqrt {2}}\)

Discussion

87.	Tan 90° is _____(a) Not defined(b) 1(c) 0(d) 2The question was asked during a job interview.I want to ask this question from Trigonometric Ratios ofSpecific Angles topic in division Trigonometry of Mathematics – Class 10
Answer» The correct option is (a) Not defined Best EXPLANATION: Tan 90° = \(\FRAC {Sin \, 90^{\circ }}{Cos \, 90^{\circ }} = \frac {1}{0}\) Any number DIVIDED with 0 is ALWAYS not defined.

Discussion

88.	\(\frac {Cos \, ⁡0^{\circ }}{1 – Sin \, ⁡30^{\circ }}\) is _____(a) 1(b) 2(c) 3(d) 4I got this question during an interview.Asked question is from Trigonometric Ratios of Specific Angles in portion Trigonometry of Mathematics – Class 10
Answer» RIGHT choice is (b) 2 Best EXPLANATION: \(\frac {COS \, ⁡0^{\circ }}{1 – Sin \, ⁡30^{\circ }} = \frac {1}{1 – 1/2}\) = \(\frac {1}{1/2}\) = 2

Discussion

89.	Trigonometric ratios are only applicable to which kind of triangles?(a) Right-angled triangles(b) Any type of triangles(c) Acute angled triangles(d) Obtuse angled trianglesI have been asked this question in a national level competition.Origin of the question is Trigonometric Ratios in section Trigonometry of Mathematics – Class 10
Answer» The correct OPTION is (a) Right-angled triangles Best explanation: Trigonometric ratios are only applicable to right-angled triangles whose angle is 90° between TWO SIDES of a TRIANGLE.

Discussion

Explore topic-wise InterviewSolutions in .

Evaluate \(\sqrt {\frac {1 – sin⁡ \, ⁡A}{1 + sin \, ⁡⁡A}}\).(a) cos A + tan A(b) cos A – tan A(c) tan A – cot A(d) sec A + tan AThis question was posed to me in unit test.This intriguing question comes from Trigonometric Identities in section Trigonometry of Mathematics – Class 10

What is the product of cot 42° and tan 48°?(a) Cot^2 42°(b) Tan^2 42°(c) 2Tan 16°(d) 2Cot 16°The question was asked in an online interview.I need to ask this question from Trigonometric Ratios of Complementary Angles in division Trigonometry of Mathematics – Class 10

Sec 75° equals to _____(a) cosec 15°(b) sec 15°(c) 1(d) 0I had been asked this question by my college professor while I was bunking the class.This is a very interesting question from Trigonometric Ratios of Complementary Angles topic in portion Trigonometry of Mathematics – Class 10

Cosec 90° is _____(a) 0(b) 2(c) 1(d) √3I got this question in an interview for internship.I would like to ask this question from Trigonometric Ratios of Specific Angles topic in division Trigonometry of Mathematics – Class 10

If cos C = \(\frac {8}{17}\) and sec C = \(\frac {17}{8}\), then 1 is the product of cos C and sec C.(a) False(b) TrueI got this question in final exam.My question is based upon Trigonometric Ratios topic in division Trigonometry of Mathematics – Class 10

Find the value of tan 225°.(a) \(\frac {1}{\sqrt 2}\)(b) 1(c) -√2(d) \(\frac {-1}{\sqrt 2}\)I got this question in an online interview.This interesting question is from Trigonometric Ratios of Complementary Angles in section Trigonometry of Mathematics – Class 10

Cot 405° equals to _____(a) cosec 15°(b) sec 15°(c) 1(d) 0The question was asked in exam.This question is from Trigonometric Ratios of Complementary Angles in portion Trigonometry of Mathematics – Class 10

The sum of two angles in ∆ABC is supplementary with the right angle at B.(a) False(b) TrueThe question was asked during an internship interview.This intriguing question comes from Trigonometric Ratios of Complementary Angles in portion Trigonometry of Mathematics – Class 10

If sin A = \(\frac {8}{17}\), what will be the value of cos A sec A?(a) 2(b) -1(c) 1(d) 0This question was posed to me by my college director while I was bunking the class.My doubt is from Trigonometric Ratios in section Trigonometry of Mathematics – Class 10

Trigonometry is also applicable to obtuse angles triangles.(a) True(b) FalseI have been asked this question in final exam.I'd like to ask this question from Trigonometric Ratios in portion Trigonometry of Mathematics – Class 10

Sec (360° – θ) is _____(a) sine of angle θ(b) secant of angle θ(c) tan of angle θ(d) cot of angle θThis question was addressed to me during an interview.The question is from Trigonometric Ratios of Complementary Angles in section Trigonometry of Mathematics – Class 10

\(\frac {Cos A}{Sin A}\) = ______(a) Tan A(b) Sin A(c) Cot A(d) Sec AThe question was posed to me in final exam.Asked question is from Trigonometric Ratios topic in division Trigonometry of Mathematics – Class 10

If tan θ = \(\frac {3}{4}\) then the value of sinθ is _________(a) \(\frac {3}{5}\)(b) \(\frac {4}{4}\)(c) \(\frac {3}{4}\)(d) \(\frac {-3}{5}\)This question was posed to me during an interview.My question is from Trigonometric Ratios topic in portion Trigonometry of Mathematics – Class 10

Evaluate tan^2 A + (1 + sec A) (sec A – 1).(a) 3 tan^2 A(b) 0(c) 2tan^2 A(d) 1The question was posed to me during an online exam.My question comes from Trigonometric Identities topic in division Trigonometry of Mathematics – Class 10

(sin A – cos A)^2 is equal to _____(a) 1 + 2sin A cos A(b) 1 – 2sin A cos A(c) 2sin A cos A – 1(d) 2sin A cos A + 1I have been asked this question in semester exam.This interesting question is from Trigonometric Identities in chapter Trigonometry of Mathematics – Class 10

Evaluate \(\frac {Cot \, 54^{\circ }}{tan \, ⁡36^{\circ }}\).(a) 0(b) 1(c) \(\frac {4}{3}\)(d) \(\frac {3}{4}\)The question was posed to me at a job interview.The above asked question is from Trigonometric Ratios of Complementary Angles topic in portion Trigonometry of Mathematics – Class 10

What is the value of sec 0° + cosec 90°?(a) 0(b) 2(c) 1(d) ∞I had been asked this question during an interview for a job.The doubt is from Trigonometric Ratios ofSpecific Angles topic in section Trigonometry of Mathematics – Class 10

60° lies in the_____ quadrant.(a) first(b) second(c) third(d) fourthThis question was posed to me during an online interview.This is a very interesting question from Trigonometric Ratios of Specific Angles topic in portion Trigonometry of Mathematics – Class 10

What is the value of sin 0° + cos 0°?(a) 0(b) 2(c) 1(d) ∞I have been asked this question during an interview.This key question is from Trigonometric Ratios of Specific Angles topic in portion Trigonometry of Mathematics – Class 10

What is the value of cos A sec A + sin A cosec A – tan A cot A?(a) 0(b) 2(c) 1(d) 3I got this question in an interview for internship.This interesting question is from Trigonometric Ratios topic in chapter Trigonometry of Mathematics – Class 10

135° lies in the third quadrant.(a) True(b) FalseThis question was posed to me in a national level competition.I want to ask this question from Trigonometric Ratios ofSpecific Angles topic in chapter Trigonometry of Mathematics – Class 10

Evaluate (cosec A – 1) (cosec A + 1) (sec^2 A – 1).(a) 0(b) 1(c) \(\frac {4}{3}\)(d) \(\frac {3}{4}\)The question was posed to me in an interview for job.I would like to ask this question from Trigonometric Identities topic in portion Trigonometry of Mathematics – Class 10

(1 – sin^2 A) (1 + tan^2 A) equals to _____(a) – Sec^2 θ Tan^2 θ(b) – Sec^2 θ Tan^2 θ(c) 1(d) 0I got this question during an interview.I'd like to ask this question from Trigonometric Identities in section Trigonometry of Mathematics – Class 10

What is the value of cos 45° + sin 45°?(a) 1(b) \( \frac {1}{4}\)(c) \( \frac {3}{4}\)(d) √2The question was posed to me in unit test.I'm obligated to ask this question of Trigonometric Ratios ofSpecific Angles topic in division Trigonometry of Mathematics – Class 10

Evaluate sin^2 30.(a) 2(b) 0(c) \( \frac {1}{4}\)(d) ∞This question was posed to me in my homework.My doubt stems from Trigonometric Ratios ofSpecific Angles in portion Trigonometry of Mathematics – Class 10

(sin A + cos A)^2 is equal to _____(a) 1 + 2sin A cos A(b) 1 – 2sin A cos A(c) 2sin A cos A – 1(d) 2sin A cos A + 1This question was addressed to me in an international level competition.The origin of the question is Trigonometric Identities in portion Trigonometry of Mathematics – Class 10

Sin (270° – x) equals to ______(a) -cos x(b) cot x(c) -cosec x(d) sec xThis question was addressed to me in final exam.The above asked question is from Trigonometric Ratios of Complementary Angles topic in portion Trigonometry of Mathematics – Class 10

Find the value of cos 135°.(a) \(\frac {1}{\sqrt {2}}\)(b) √2(c) -√2(d) \(\frac {-1}{\sqrt {2}}\)This question was addressed to me during a job interview.The query is from Trigonometric Ratios of Complementary Angles in division Trigonometry of Mathematics – Class 10

Tan 90° is _____(a) Not defined(b) 1(c) 0(d) 2The question was asked during a job interview.I want to ask this question from Trigonometric Ratios ofSpecific Angles topic in division Trigonometry of Mathematics – Class 10

\(\frac {Cos \, ⁡0^{\circ }}{1 – Sin \, ⁡30^{\circ }}\) is _____(a) 1(b) 2(c) 3(d) 4I got this question during an interview.Asked question is from Trigonometric Ratios of Specific Angles in portion Trigonometry of Mathematics – Class 10