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Evaluate \(\frac {1+cos \, \theta }{sin \, \theta } \)(cosec θ – cot θ).(a) cosec θ + cot θ(b) cot^2 θ + tan^2 θ(c) cot θ – tan θ(d) cosec^2 θ – cot^2 θThe question was asked in quiz.My doubt stems from Trigonometric Identities in section Trigonometry of Mathematics – Class 10 |
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Answer» CORRECT choice is (d) cosec^2 θ – cot^2 θ To EXPLAIN I would SAY: \(\frac {1+cos \, \THETA }{sin \, \theta } \)(cosec θ – cot θ) = \(\frac {1}{sin \, \theta }+ \frac {cos \, \theta }{sin \, \theta } \)(cosec θ – cot θ) = (cosec θ + cot θ)(cosec θ – cot θ) = cosec^2 θ – cot^2 θ |
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