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\(\frac {Sin \theta }{Cos \theta}\) equals to ______(a) tan θ(b) cot θ(c) cosec θ(d) sec θThe question was asked in homework.My question is from Trigonometric Ratios in section Trigonometry of Mathematics – Class 10

Answer»

Correct answer is (a) TAN θ

For explanation I would say: SIN θ = \(\frac {Length \, of \, opposite \, side \, of \, the \, triangle}{Length \, of \, HYPOTENUSE \, of \, the \, triangle}\)

Cos θ = \(\frac {Length \, of \, adjacent \, side \, of \, the \, triangle}{Length \, of \, hypotenuse \, of \, the \, triangle}\)

\(\frac {Sin \THETA }{Cos \theta} = \frac {Length \, of \, opposite \, side \, of \, the \, triangle}{Length \, of \, adjacent \, of \, the \, triangle}\)

= Tan θ


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