A ball is thrown up with an initial velocity of 20 m/s and after some time it returns. What is the maximum height reached? Take g = 10 m/s^2.(a) 80m(b) 20m(c) 70m(d) 40mI have been asked this question by my college professor while I was bunking the class.Enquiry is from Kinematic Equations for Uniformly Accelerated Motion in section Motion in a Straight Line of Physics – Class 11

A ball is thrown up with an initial velocity of 20 m/s and after some

1.	A ball is thrown up with an initial velocity of 20 m/s and after some time it returns. What is the maximum height reached? Take g = 10 m/s^2.(a) 80m(b) 20m(c) 70m(d) 40mI have been asked this question by my college professor while I was bunking the class.Enquiry is from Kinematic Equations for Uniformly Accelerated Motion in section Motion in a Straight Line of Physics – Class 11
Answer» Correct answer is (b) 20m Best explanation: Here we will use the third EQUATION of motion. The third equation of motion is V^2 = u^2 + 2as. At the MAXIMUM height, the velocity of the ball will be zero, THEREFORE, v = 0, u = 20, and a = -g = -10. On solving, we will get s = 20m.

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