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A ball of mass 100 g, projected at an angle of 30° from the ground with an initial velocity of 11 m/s, acceleration due to gravity is g = 10 m/s^2, what is the maximum height attained?(a) 1.5 m(b) 3.0 m(c) 1.0 m(d) 2.0 mThe question was posed to me by my school principal while I was bunking the class.This is a very interesting question from Simple Projectile Motion in chapter Motion in a Plane of Physics – Class 11

Answer»

The correct choice is (a) 1.5 m

The best explanation: The formula for maximum height is H = (V sinθ)^2/2g. Here, v = 11, θ = 30°, G = 10. Hence, on SOLVING we will get the maximum height attained as 1.5125 m. The value can be rounded off to 1.5.



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