1.

A bat can hear sound of frequencies up to 120 kHz. Determine the minimum wavelength of sound which it can hear. Take speed of sound in air to be 344 ms^(-1)

Answer»

Solution :Given , F= 120 kHz = `120 xx 10^3 HZ, V= 344 m s^(-1)`
From RELATION `V = flambda`
WAVELENGTH `lambda = V/f = (344)/(120xx10^3)`
`=2.87xx10^(-3) m ` ( or 2.87 mm)
i.e. , the bat can hear sound of minimum wavelength 2.87 mm.


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