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A beam of specific kind of particles of velocity `2.1 xx 10^7 m//s` is scattered by a gold `(Z = 79)` nuclei. Find out specific charge (charge/mass) of this particle if the distance of closest approach is `2.5 xx 10^-14 m`.A. `4.84 xx 10^7 C//g`B. `4.84 xx 10^-7 C//g`C. `2.42 xx 10^7 C//g`D. `3 xx 10^-12 C//g` |
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Answer» Correct Answer - A (a) `(1)/(2) mv^2 = (k(Zq_1)q_2)/( r)` `rArr (q_2)/(m) = (r.v^2)/(2k.q_1.Z)` `(q_2)/(m) = (2.5 xx 10^-14 xx (2.1 xx 10^7)^2)/(2xx 9 xx 10^9 xx 70 xx 1.6 xx 10^-19)` `4.84 xx 10^7 C//g`. |
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