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InterviewSolution
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A black body with surface area 0.001 `m^(2)` is heated upto a temperature 400 K and is suspended in a room temperature 300K. The intitial rate of loss of heat from the body to room isA. 10 WB. 1WC. 0.1WD. 0.5 W |
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Answer» Correct Answer - B b) The rate of heat emission, u = `sigmaAT^(4)`. At room temperatures to the rate of absorption is `u_(0)=sigmaAT_(0)^(4)` The net rate of heat loss. `u-u_(0)=sigmaA(T^(4)-T_(0)^(4))` Given that A=0.001`m^(2)` T=400K and `T_(0)`=300K Thus, `u-u_(0)` = `5.67 xx 10^(-8) xx 0.001 xx [(400)^(4)-(300)^(4)]`=0.99 W |
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