InterviewSolution
Saved Bookmarks
| 1. |
A black rectangular surface of area A emits energy E per second at `27^circC`. If length and breadth are reduced to one third of initial value and temperature is raised to `327^circC`, then energy emitted per second becomesA. `(4E)/(9)`B. `(7E)/(9)`C. `(10E)/(9)`D. `(16E)/(9)` |
|
Answer» Correct Answer - D `T_(1)=27+273=300K,L_(2)=(1)/(3)L_(1)` `T_(2)=273+32=600K` `(E_(2))/(E_(1))=(A_(2))/(A_(1))((T_(2))/(T_(1)))^(4)` `=(L_(2)b_(2))/(L_(1)b_(1))xx((600)/(300))^(4)` `=(1)/(3)xx(1)/(3)=16` `E_(2)=(16)/(9)E_(1)`. |
|