InterviewSolution
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When the observer moves towards the stationary source with velocity, `v_1`, the apparent frequency of emitted note is `f_1`. When the observer moves away from the source with velocity `v_1`, the apparent frequency is `f_2`. If v is the velocity of sound in air and `f_1/f_2` = 2,then `v/v_1` = ?A. 2B. 3C. 4D. 5 |
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Answer» Correct Answer - B `F_(1)=(F[v+v_(1)])/(v),F_(2)(F[v-v_(2)])/(v)` `(F_(1))/(F_(2))=(F[v+v_(1)])/(v)xx(v)/(F[v-v_(1)])` `2=(v+v_(1))/(v-v_(1))` `2v-2v_(1)=v_(1)+v` `v=3v_(1)` `(v)/(v_(1))=3` |
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