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In vertical circular motion, the ratio of kinetic energy of a particle at highest point to that at lowest point isA. 5B. 2C. `0.5`D. `0.2` |
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Answer» Correct Answer - D `(KE_(H))/(KE_(L))=((1)/(2)mv_(H)^(1))/((1)/(2)mv_(L)^(2))=(rg)/(5rg)=0.2` |
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