1.

A block having mass m collides with another stationary block having mass 2m. The lighter block comes to rest after collison. If the velocity of first block is V, then the value of co-efficient of resitution will be

Answer»

0.5
0.4
0.6
0.8

Solution :By CONSERVATION of MOMENTUM
`mV=2mV^(1)impliesV^(1)=V/2`
`e=("VEL. of separation")/("Velocity of APPROACH")=0.5`


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