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A block having mass m collides with another stationary block having mass 2m. The lighter block comes to rest after collison. If the velocity of first block is V, then the value of co-efficient of resitution will be |
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Answer» 0.5 `mV=2mV^(1)impliesV^(1)=V/2` `e=("VEL. of separation")/("Velocity of APPROACH")=0.5` |
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