1.

A block of iron floats on mercury. Find the fractionof volume which remains immersed in mercury. (Densities of iron and mercury are 7.8gcm^(-3) and 13.6gcm^(-3) respectively).

Answer»

Solution :Let V be the volume of IRON block and v be its volume immersed in MERCURY. For floatation.
Weight of block = Weight of mercury displaced by the immersed portion of block.
i.e. `Vxx7.8xxg=vxx13.6xxg`
or `v/V=7.8/3.6=0.574`
or `v=0.574V`
The fraction 0.574 of TOTAL volume will REMAIN immersed in mercury.


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