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A block of mass 500 g is at rest on a horizontal table. What steady force is required to give the block a velocity of 200"cms"^(-1)" in 4 s ?" |
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Answer» Solution :Use F=ma `a=(v-u)/(t)=(200-0)/(4)=50cm//s^(2)` `F=500 xx 50=25,000"DYNE".` |
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