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A block of wood floats on water with 2/5 th of its volume above the water surface. Calculate the density of wood. |
Answer» SOLUTION :Let the volume of block be V and density of wood be `rho`. Volume of block above the surface of water `=2/5V` `:.` Volume of block immersed `v=V-2/5V=3/5V` By the PRINCIPLE of floatation Weight of the block `=` Weight of water DISPLACED by the immersed part of block i.e. `Vxxrhoxxg=3/5Vxx1xxg` `rho=3/5=0.6gcm^(-3)` (Here the density of water is taken as `1gcm^(-3)`) |
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